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R S Agrawal 3G Class 9 Prove a^3+b^3+c^3 - 3abc = 1/2 (a+b+c){(a-b)^2 + (b-c)^2 + (c-a)^2} Hindi Me
04:32 6.23 MB 223,034
a³+b³+c³-3abc | a³+b³+c³-3abc formula | a³+b³+c³-3abc =? | Factorise a³+b³+c³-3abc | Identity
03:28 4.76 MB 785,583
Important identity | Algebra | Class 9 | Class 10 | if a+b+c=0 then prove that a3+b3+c3 = 3abc
01:51 2.54 MB 785,732
prove that a³ + b³+ c³ - 3abc = ( a + b + c) ( a² + b² + c ² - ab - bc - ca )
07:55 10.87 MB 505,610
🎵 Featured Track Info & Notes: R S Agrawal 3G Class 9 Prove a^3+b^3+c^3 - 3abc = 1/2 (a+b+c){(a-b)^2 + (b-c)^2 + (c-a)^2} Hindi Me
Top Result #1Artist / Channel: Mathssmart Hindi | Runtime: 04:32 mins | Views / Streams: 223,034